0.00018=x^2/0.14-x

Solution for 0.00018=x^2/0.14-x equation:

0.00018=x^2/0.14-x

We move all terms to the left:

0.00018-(x^2/0.14-x)=0


Domain of the equation: 0.14-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-0.14

x!=-0.14/1

x!=-0.14

x∈R


We get rid of parentheses

-x^2/0.14+x+0.00018=0

We multiply all the terms by the denominator


-x^2+x*0.14+(0.00018)*0.14=0

We add all the numbers together, and all the variables

-1x^2+x*0.14-5+2.52E=0

Wy multiply elements

-1x^2+0.14x-5+2.52E=0

We add all the numbers together, and all the variables

-1x^2+0.14x+1.8500702077168=0

a = -1; b = 0.14; c = +1.8500702077168;
Δ = b2-4ac
Δ = 0.142-4·(-1)·1.8500702077168
Δ = 7.4198808308672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.14)-\sqrt{7.4198808308672}}{2*-1}=\frac{-0.14-\sqrt{7.4198808308672}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.14)+\sqrt{7.4198808308672}}{2*-1}=\frac{-0.14+\sqrt{7.4198808308672}}{-2}
$